Teorema de Thales

If three or more parallels
If three or more paral-le-lels
If three or more parallels
If three or more paral-le-lels
Are cut, are cut
By two transversals, by two transversals
If three or more paral-le-lels
Are cut, are cut
Two segments of one of these
Any two segments
Two segments of one of these
Are proportional
To the two segments
Corresponding from the other

A parallel to B
B parallel to C
A parallel, B parallel, C parallel. D
OP is to PQ
MN is to NT
OP is to PQ as MN is to NT
A parallel B
B parallel C
OP is to PQ as MN is to NT

The bisector I will draw
And intersect four planes
An equality I will find
OP plus PQ is equal to ST
I will use the hypotenuse
Oh, don't complicate yourself, no one uses it
I will draw, then, a cathetus
I don't get involved, I don't get involved

Triangle, quadrilateral, pentagon, hexagon
Heptagon, octagon, they are all polygons
Sine, cosine, tangent and secant
And cosecant, and cotangent
Thales, Thales of Miletus
Thales, Thales of Miletus
That's what we wanted to prove

Supposedly what we wanted wanted
To prove prove prove